18=x^2/(0.05-x)(0.1-x)

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Solution for 18=x^2/(0.05-x)(0.1-x) equation: 



18=x^2/(0.05-x)(0.1-x)

We move all terms to the left:

18-(x^2/(0.05-x)(0.1-x))=0



Domain of the equation: (0.05-x)(0.1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.1-x)!=-0.05

x∈R



We add all the numbers together, and all the variables

-(x^2/(-1x+0.05)(-1x+0.1))+18=0

We multiply parentheses ..

-(x^2/(+x^2-0.1x-0.05x+0.005))+18=0

We multiply all the terms by the denominator


-(x^2+18*(+x^2-0.1x-0.05x+0.005))=0



We calculate terms in parentheses: -(x^2+18*(+x^2-0.1x-0.05x+0.005)), so:

x^2+18*(+x^2-0.1x-0.05x+0.005)

We multiply parentheses

x^2+18x^2+0x+0x+0.09

We add all the numbers together, and all the variables

19x^2+2x+0.09

Back to the equation:

-(19x^2+2x+0.09)



We get rid of parentheses

-19x^2-2x-0.09=0

a = -19; b = -2; c = -0.09;
Δ = b2-4ac
Δ = -22-4·(-19)·(-0.09)
Δ = -2.84
Delta is less than zero, so there is no solution for the equation

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